'''
Created on Mar 7, 2010
@author: Diego
需求: 得到某个目录下, 符合过滤条件的文件夹/文件.
实现: 将os.walk再次包装.
TODO: 不知道本程序的做法, 和传统的逐个目录列举的方法, 哪个效率更高. 待测试.
'''
import
os
import
os.path
os.path.sep
=
"
/
"
path
=
"
/media/dev/project/google_codes/srgjs
"
EXCLUDE_DIR_LIST
=
[
"
.SVN
"
,
"
CVS
"
]
EXCLUDE_FILE_LIST
=
[
"
.CVSIGNORE
"
]
def
is_parent_exclude(parentPath,excludeDirList):
ss
=
parentPath.split(
"
/
"
);
for
s
in
ss:
if
(s.upper()
in
excludeDirList):
return
True
return
False
def
filter_walk(targetDirectory,excludeDirList,excludeFileExtList):
dirList
=
[]
fileList
=
[]
for
(parent, dirs, files)
in
os.walk(targetDirectory):
for
d
in
dirs:
if
(d.upper()
in
excludeDirList):
continue
#
To check if one of the parent dir should be excluded.
if
(is_parent_exclude(parent,excludeDirList)):
continue
dirList.append(parent
+
"
/
"
+
d)
for
f
in
files:
if
(f.upper()
in
excludeFileExtList):
continue
#
To check if one of the parent dir should be excluded.
if
(is_parent_exclude(parent,excludeDirList)):
continue
fileList.append(parent
+
"
/
"
+
f)
return
(dirList,fileList)
#
test
dirs,files
=
filter_walk(path,EXCLUDE_DIR_LIST,EXCLUDE_FILE_LIST)
for
d
in
dirs:
print
d
for
f
in
files:
print
f