nPOJ 1503 Integer Inquiry
–Description
省略
–Input
The input will consist of at most 100 lines of text, each of which contains a single VeryLongInteger. Each VeryLongInteger will be 100 or fewer characters in length, and will only contain digits (no VeryLongInteger will be negative).
The final input line will contain a single zero on a line by itself.
–Output
Your program should output the sum of the VeryLongIntegers given in the input.
–Sample Input
•123456789012345678901234567890
•123456789012345678901234567890
•123456789012345678901234567890
•0
–Sample Output
•370370367037037036703703703670
题解：
import java.io.*;
import java.util.*;
import java.math.BigInteger;
public class Main {
public static void main(String[] args){
BigInteger sum=new BigInteger("0");
BigInteger num;
Scanner cin=new Scanner(System.in);
for(;;)
{
num=cin.nextBigInteger();
if(num.toString()=="0")break;
sum=sum.add(num);
}
System.out.println(sum.toString());
}
}
补方法如下：
add
public BigInteger add(BigInteger val) throws ArithmeticException
- 返回一个 BigInteger ，其值是 (this + val) 。
subtract
public BigInteger subtract(BigInteger val)
- 返回一个 BigInteger ，其值是 (this - val) 。
multiply
public BigInteger multiply(BigInteger val)
- 返回一个 BigInteger ，其值是 (this * val) 。
divide
public BigInteger divide(BigInteger val) throws ArithmeticException
- 返回一个 BigInteger ，其值是 (this / val) 。 如果 val == 0 ，则抛出 ArithmeticException 。
remainder
public BigInteger remainder(BigInteger val) throws ArithmeticException
- 返回一个 BigInteger ，其值是 (this % val) 。 如果 val == 0，则抛出 ArithmeticException 。